7za.exe ansprechen

Vielleicht hilft das:
http://www.autoitscript.com/forum/topic/85…post__p__610129

Hallo Molaynox,

das sind die möglichen Parameter der 7Za.exe:

Zitat

7-Zip (A) 4.32 Copyright (c) 1999-2005 Igor Pavlov 2005-12-09

Usage: 7za <command> [<switches>...] <archive_name> [<file_names>...]
[<@listfiles...>]

<Commands>
a: Add files to archive
d: Delete files from archive
e: Extract files from archive (without using directory names)
l: List contents of archive
t: Test integrity of archive
u: Update files to archive
x: eXtract files with full paths
<Switches>
-ai[r[-|0]]{@listfile|!wildcard}: Include archives
-ax[r[-|0]]{@listfile|!wildcard}: eXclude archives
-bd: Disable percentage indicator
-i[r[-|0]]{@listfile|!wildcard}: Include filenames
-m{Parameters}: set compression Method
-o{Directory}: set Output directory
-p{Password}: set Password
-r[-|0]: Recurse subdirectories
-sfx[{name}]: Create SFX archive
-si[{name}]: read data from stdin
-so: write data to stdout
-t{Type}: Set type of archive
-v{Size}[b|k|m|g]: Create volumes
-u[-][p#][q#][r#][x#][y#][z#][!newArchiveName]: Update options
-w[{path}]: assign Work directory. Empty path means a temporary directory
-x[r[-|0]]]{@listfile|!wildcard}: eXclude filenames
-y: assume Yes on all queries

Alles anzeigen

Mit diesem Wissen kannst du dir dann ganz einfach das Skript erstellen:

$archivName = 'test.7z' ;Name des zu entpackenden Archivs
$Files = 'c*.*' ;zu entpackende Dateinamen hier alle die mit c beginnen
Run('7Za.exe e ' & $archivName & ' ' & $Files & '"',@ScriptDir,@SW_HIDE)

frohe Weihnachten autoBert

Probiere es mal so:

$7zip = "7z.exe "
$source = "c:\Tmp\ "
$dest = "c:\Temp\Test.7z "
$command = "a "
$switches = "-r -t7z -mx7"
ConsoleWrite($7zip & $command & $dest & $source & $switches & @CRLF)
$pid = RunWait(@ComSpec & " /k " & $7zip & $command & $dest & $source & $switches, @ScriptDir, @SW_MAXIMIZE)

Gruß,
UEZ