Algemeine Frage zu Array

trallala

ich möchte 25 Zahlenkollonen in je 3 Felder dimensionieren, also "nicht Eindimensional" bsp. aus Turo-pascal:

Extra : array[1..14, 0..2] of real =
((299.77, 0.107408,0.000325), (251.88, 0.016321,0.000165),
(251.83,26.651886,0.000164), (349.42,36.412478,0.000126),
( 84.66,18.206239,0.000110), (141.74,53.303771,0.000062),
(207.14, 2.453732,0.000060), (154.84, 7.306860,0.000056),
( 34.52,27.261239,0.000047), (207.19, 0.121824,0.000042),
(291.34, 1.844379,0.000040), (161.72,24.198154,0.000037),
(239.56,25.513099,0.000035), (331.55, 3.592518,0.000023));

es sollen 25 Gruppen(jede in einer klammer hier dargestellt) die jeweils 3 Werte aufweisen dimensioniert werden.

Ist diese Art der Dimensionierung in Autoit überhaupt realisierbar ?

**GtaSpider**

Hallo!

Ja das lässt sich mit AutoIt leicht realiesierbaren:

Code

Dim $TestArray[5][5][5];Also ein array das 5*5*5 mögliche strings erhalten kann!
$TestArray[1][1][1] = "Test001"
$TestArray[1][1][2] = "Test002
$TestArray[2][1][3] = "Test003"
$TestArray[3][4][3] = "Test004"

Mfg Spider

ytwinky

Hi,
in der Hilfe wird auch beschreiben, wie du das Array gleich beim Deklarieren auch initialisieren kannst(also fast pascal-like).
Gruß
ytwinky

trallala

So ich habe das Problem jetz gelöst.

Spoiler anzeigen

#include <Array.au3>
Dim $isA[14][3] = _
[[299.77,0.107408,0.000325],[251.88, 0.016321,0.000165],[251.83,26.651886,0.000164], _
[349.42,36.412478,0.000126],[84.66,18.206239,0.000110],[141.74,53.303771,0.000062], _
[207.14, 2.453732,0.000060],[154.84, 7.306860,0.000056],[34.52,27.261239,0.000047], _
[207.19, 0.121824,0.000042],[291.34, 1.844379,0.000040],[161.72,24.198154,0.000037], _
[239.56,25.513099,0.000035],[331.55, 3.592518,0.000023]]

Msgbox(0,"Test", $isA[7][1])

das Ergebnis = 7.30686

Ja - Damit kann ich leben :musik1: